2y/y-1=5/y+(10-8y)/(y^2-y)

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Solution for 2y/y-1=5/y+(10-8y)/(y^2-y) equation:


D( y )

y = 0

y^2-y = 0

y = 0

y = 0

y^2-y = 0

y^2-y = 0

y^2-y = 0

DELTA = (-1)^2-(0*1*4)

DELTA = 1

DELTA > 0

y = (1^(1/2)+1)/(1*2) or y = (1-1^(1/2))/(1*2)

y = 1 or y = 0

y in (-oo:0) U (0:1) U (1:+oo)

(2*y)/y-1 = (10-(8*y))/(y^2-y)+5/y // - (10-(8*y))/(y^2-y)+5/y

(2*y)/y-((10-(8*y))/(y^2-y))-(5/y)-1 = 0

(2*y)/y-((10-8*y)/(y^2-y))-5*y^-1-1 = 0

(-1*(10-8*y))/(y^2-y)-5/y-1+2 = 0

y^2-y = 0

y^2-y = 0

y*(y-1) = 0

y-1 = 0 // + 1

y = 1

y*(y-1) = 0

(-1*(10-8*y))/(y*(y-1))-5/y-1+2 = 0

(-1*(10-8*y))/(y*(y-1))+(-5*(y-1))/(y*(y-1))+(2*y*(y-1))/(y*(y-1))+(-1*y*(y-1))/(y*(y-1)) = 0

2*y*(y-1)-1*(10-8*y)-5*(y-1)-1*y*(y-1) = 0

2*y^2-y^2+3*y-2*y+y-5 = 0

2*y^2-y^2+y+y-5 = 0

y^2+2*y-5 = 0

y^2+2*y-5 = 0

y^2+2*y-5 = 0

DELTA = 2^2-(-5*1*4)

DELTA = 24

DELTA > 0

y = (24^(1/2)-2)/(1*2) or y = (-24^(1/2)-2)/(1*2)

y = (2*6^(1/2)-2)/2 or y = (-2*6^(1/2)-2)/2

(y-((-2*6^(1/2)-2)/2))*(y-((2*6^(1/2)-2)/2)) = 0

((y-((-2*6^(1/2)-2)/2))*(y-((2*6^(1/2)-2)/2)))/(y*(y-1)) = 0

((y-((-2*6^(1/2)-2)/2))*(y-((2*6^(1/2)-2)/2)))/(y*(y-1)) = 0 // * y*(y-1)

(y-((-2*6^(1/2)-2)/2))*(y-((2*6^(1/2)-2)/2)) = 0

( y-((-2*6^(1/2)-2)/2) )

y-((-2*6^(1/2)-2)/2) = 0 // + (-2*6^(1/2)-2)/2

y = (-2*6^(1/2)-2)/2

( y-((2*6^(1/2)-2)/2) )

y-((2*6^(1/2)-2)/2) = 0 // + (2*6^(1/2)-2)/2

y = (2*6^(1/2)-2)/2

y in { (-2*6^(1/2)-2)/2, (2*6^(1/2)-2)/2 }

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